Here is Basic Geometry problem .Which will help you to understand ,finding a point of interaction and the Shortest distance between a point and a line .
We are using Distance Formula to solve this .
Find the Shortest Distance between to the given point and the Line
(2,3) , y=x-6
Answer:
The slope of Line y=x-6 is equal to 1
The slope of the perpendicular line is -1
The equation of the line joining the point (2,3) and the perpendicular line is given by
Substitute x1 as 2 and y1 as 3 (given in question )
Substitute this in y = x-6
So the point of intersection is { 11/2,-1/2}.
Now the shortest distance between This and (2,3) is given by using distance formula
d = √[(2-11/2)2+(3+1/2)2]
= 4.95
approximately 5.
We are using Distance Formula to solve this .
Find the Shortest Distance between to the given point and the Line
(2,3) , y=x-6
Answer:
The slope of Line y=x-6 is equal to 1
The slope of the perpendicular line is -1
The equation of the line joining the point (2,3) and the perpendicular line is given by
(y-y1)=m(x-x1)Here m is the slope which is -1
Substitute x1 as 2 and y1 as 3 (given in question )
y-3 = -1(x-2) y-3 = -x+2 x+y-5=0 -----1Then solve the following system of equations to get the point of intersection
  y =x-6 we can write it as x-y =6
                   x+y=5 (1)
           (add) ________________
                   2x=11
                        11
                     X= --
                         2           
Substitute this in y = x-6
 
     11
y =  -----  -  6
      2
      - 1
y  =  -----
       2
So the point of intersection is { 11/2,-1/2}.
Now the shortest distance between This and (2,3) is given by using distance formula
d = √[(2-11/2)2+(3+1/2)2]
= 4.95
approximately 5.
 
No comments:
Post a Comment